QJEEM18Ph18c4: JEE Main 2018 Physics - Class 12 JEEM18Ph18c4 Solution: A charge q is spread uniformly over an insulated loop of radius …

Question

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A charge q is spread uniformly over an insulated loop of radius r. If it is rotated with an angular velocity

ω

with resect to normal axis then the magnetic moment of the loop is :

Accepted Answer

Magnetic moment,

μ

= I A

=

\frac{q}{T} (π r^{2})

=

\frac{q}{2 π / ω} (π r^{2})

=

\frac{q w}{2 π}

(π r^{2})

=

\frac{1}{2}

q

ω

r²

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