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QJEEM18Ph0220: JEE Main 2018 Physics - Class 11 JEEM18Ph0220 Solution: One mole of an ideal monoatomic gas is compressed isothermally…
One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, The work done on the gas will be :
Multiple Choice Options
- A 300 R
- B 300 R ln 6
- C 300 R ln 2
- D 300 R ln 7
Step-by-Step Verified Solution
We know,
Work done on gas = nRT n
Given Pf = 2Pi
T = 27 + 273 = 300 K
and for monoatomic gas, n = 1.
Work done = 1 R 300 n(2)
= 300 R n(2)
Work done on gas = nRT
Given Pf = 2Pi
T = 27 + 273 = 300 K
and for monoatomic gas, n = 1.
= 300 R