Verified Solution • 2025–26 Session moderate

QJEEM18Ph0220: JEE Main 2018 Physics - Class 11 JEEM18Ph0220 Solution: One mole of an ideal monoatomic gas is compressed isothermally…

One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27∘C. The work done on the gas will be :

Multiple Choice Options

  • A 300 R
  • B 300 R ln 6
  • C 300 R ln 2
  • D 300 R ln 7

Step-by-Step Verified Solution

We know,

Work done on gas = nRT ℓn (PfPi)

Given Pf = 2Pi

T = 27 + 273 = 300 K

and for monoatomic gas, n = 1.

∴ Work done = 1 ×R ×300 ℓn(2)

= 300 R ℓn(2)

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