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QJEEM18Mace8b: JEE Main 2018 Mathematics - Class 11 JEEM18Mace8b Solution: If a circle C, whose radius is 3, touches externally the…

If a circle C, whose radius is 3, touches externally the circle,
x2+y2+2x−4y−4=0{x^2} + {y^2} + 2x - 4y - 4 = 0 at the point (2, 2), then the length of the intercept cut by this circle C, on the x-axis is equal to :

Multiple Choice Options

  • A 252\sqrt 5
  • B 323\sqrt 2
  • C 5\sqrt 5
  • D 232\sqrt 3

Step-by-Step Verified Solution

Given circle is :

x2 + y2 + 2x −- 4y −- 4 = 0

∴   \therefore\,\,\, its center is ( −- 1, 2) and radius is 3 units.

Let A = (x, y) be the center of the circle C

∴\therefore    \,\,\, x−12{{x - 1} \over 2} = 2 ⇒\Rightarrow x = 5 and y+22{{y + 2} \over 2} = 2 ⇒\Rightarrow y = 2

So the center of C is (5, 2) and its radius is 3

∴   \therefore\,\,\, Equation of center C is :

x2 + y2 −- 10x −- 4y + 20 = 0

∴   \therefore\,\,\, The length of the intercept it cuts on the x-axis

= 2 g2−c=225−20=25\sqrt {{g^2} - c} = 2\sqrt {25 - 20} = 2\sqrt 5

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