QJEEM18Mac3d8: JEE Main 2018 Mathematics - Class 11 JEEM18Mac3d8 Solution: Tangents drawn from the point ( − 8, 0) to the parabola y 2 =…

Equation of the chord of contact PQ is given by : T=0

or T $$\equiv$$ yy₁ $$-$$ 4(x + x₁), where (x₁, y₁) $$\equiv$$ ($$-$$8, 0)

$$\therefore$$Equation becomes : x = 8

& chord of contact is x = 8

$$\therefore$$ Coordinates of point P and Q are (8, 8) and (8, $$-$$ 8)

and focus of the parabola is F (2, 0)

$$\therefore$$ Area of triangle PQF = $$\frac{1}{2}$$ $$\times$$ (8 $$-$$ 2) $$\times$$ (8 + 8) = 48 sq. units