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QJEEM18Ma9aa8: JEE Main 2018 Mathematics - Class 11 JEEM18Ma9aa8 Solution: If the length of the latus rectum of an ellipse is 4 units and…

If the length of the latus rectum of an ellipse is 4 units and the distance between a focus an its nearest vertex on the major axis is 32{3 \over 2} units, then its eccentricity is :

Multiple Choice Options

  • A 12{1 \over 2}
  • B 13{1 \over 3}
  • C 23{2 \over 3}
  • D 19{1 \over 9}

Step-by-Step Verified Solution

If the cordinate of focus and vertex are (ae, 0) and (a, 0) respectively,

then distance between focus and vertex,

a −- ae = 32{3 \over 2} (given)

⇒\Rightarrow    \,\,\, a (1 −- e) = 32{3 \over 2}

Length of latus rectum,

2b2a=4{{2{b^2}} \over a} = 4

⇒\Rightarrow    \,\,\, b2 = 2a

⇒\Rightarrow    \,\,\, a2(1 −- e2) = 2a   [As b2 = a2 (1 −- e2)]

⇒\Rightarrow    \,\,\, a (1 −- e) ( 1 + e) = 2

Putting    a (1 −- e) = 32{3 \over 2}

⇒\Rightarrow    \,\,\, 32{3 \over 2} (1 + e) = 2

⇒\Rightarrow    \,\,\, 3 + 3e = 4

⇒\Rightarrow    \,\,\, e = 13{1 \over 3}

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