Verified Solution • 2025–26 Session moderate

QJEEM18Ma877c: JEE Main 2018 Physics - Class 11 JEEM18Ma877c Solution: If the position vectors of the vertices A, B and C of a ABC are …

If the position vectors of the vertices A, B and C of a Δ\Delta ABC are respectively 4i^+7j^+8k^,4\widehat i + 7\widehat j + 8\widehat k,     2i^+3j^+4k^,2\widehat i + 3\widehat j + 4\widehat k, and 2i^+5j^+7k^,2\widehat i + 5\widehat j + 7\widehat k, then the position vectors of the point, where the bisector of ∠\angle A meets BC is :

Multiple Choice Options

  • A 12(4i^+8j^+11k^){1 \over 2}\left( {4\widehat i + 8\widehat j + 11\widehat k} \right)
  • B 13(6i^+11j^+15k^){1 \over 3}\left( {6\widehat i + 11\widehat j + 15\widehat k} \right)
  • C 13(6i^+13j^+18k^){1 \over 3}\left( {6\widehat i + 13\widehat j + 18\widehat k} \right)
  • D 14(8i^+14j^+19k^){1 \over 4}\left( {8\widehat i + 14\widehat j + 19\widehat k} \right)

Step-by-Step Verified Solution

Suppose angular bisector of A meets BC at D(x, , z)

Using angular bisector theorem,

ABAC{{AB} \over {AC}} = BDDC{{BD} \over {DC}}

BDDC{{BD} \over {DC}} = (4−2)2+(7−3)2+(8−4)2(4−2)2+(7−5)2+(8−7)2{{\sqrt {{{\left( {4 - 2} \right)}^2} + {{\left( {7 - 3} \right)}^2} + {{\left( {8 - 4} \right)}^2}} } \over {\sqrt {{{\left( {4 - 2} \right)}^2} + {{\left( {7 - 5} \right)}^2} + {{\left( {8 - 7} \right)}^2}} }}

= 22+42+4222+22+12{{\sqrt {{2^2} + {4^2} + {4^2}} } \over {\sqrt {{2^2} + {2^2} + {1^2}} }} = 63{6 \over 3} = 2

JEE Main 2018 (Online) 15th April Evening Slot Mathematics - Vector Algebra Question 202 English Explanation

So, D(x, y, z) ≡\equiv ((2)(2)+(1)(2)2+1,(2)(5)+(1)(3)2+1\left( {{{\left( 2 \right)\left( 2 \right) + \left( 1 \right)\left( 2 \right)} \over {2 + 1}},{{\left( 2 \right)\left( 5 \right) + \left( 1 \right)\left( 3 \right)} \over {2 + 1}}} \right. , (2)(7)+(1)(4)2+1)\left. {{{\left( 2 \right)\left( 7 \right) + \left( 1 \right)\left( 4 \right)} \over {2 + 1}}} \right)

D(x, y, z) ≡\equiv (63,133,183)\left( {{6 \over 3},{{13} \over 3},{{18} \over 3}} \right)

Therefore, position vector of point p = 13{1 \over 3} (6i + 13j + 18k)

Related Learning Resources & Exam Preparation