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QJEEM18Cheab1: JEE Main 2018 Chemistry - Class 12 JEEM18Cheab1 Solution: The main reduction product of the following compound with NaBH…

The main reduction product of the following compound with NaBH4 in methanol is :

JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 209 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/9ae757ac362d964a9b048b40bd666745282851c422918c433a4e957a5b8e59e0.webp
  • B https://ik.imagekit.io/novatra/photos/838608c891552bd78095954a6e98d49d464d287c21b69573ded4267b31071011.webp
  • C https://ik.imagekit.io/novatra/photos/3326fe09210587d12ad77ca25e7034913f880a72af998d037d883996642e7ad0.webp
  • D https://ik.imagekit.io/novatra/photos/a087b3afcd1a10112d77718ea90701239ba5aa6d1feb08893ca55d48928a0936.webp

Step-by-Step Verified Solution

JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 209 English Explanation
Sodium borohydride reduces ketonic group to alcohol but not the amide group and C = C double bond.

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