Verified Solution • 2025–26 Session moderate

QJEEM18Chd66d: JEE Main 2018 Chemistry - Class 11 JEEM18Chd66d Solution: The correct match between items of List-I and List-II is : .tg…

The correct match between items of List-I and List-II is :

List - I List - II
(A) Coloured impurity (P) Steam distilation
(B) Mixture of o-nitrophenol
and p-nitrophenol
(Q) Fractional distilation
(C) Crude Naphtha (R) Charcoal treatment
(d) Mixture of glycerol
and sugars
(S) Distillation under
reduced pressure

Multiple Choice Options

  • A (A)-(R), (B)-(S), (C)-(P), (D)-(Q)
  • B (A)-(R), (B)-(P), (C)-(S), (D)-(Q)
  • C (A)-(R), (B)-(P), (C)-(Q), (D)-(S)
  • D (A)-(P), (B)-(S), (C)-(R), (D)-(Q)

Step-by-Step Verified Solution

(a) Charcoal treatment removes coloured impurity through adsorption.

(b) Steam distillation separates the mixture of o-nitrophenol and p-nitrophenol. The o-nitrophenol is steam volatile (due to intramolecular hydrogen bonding), and the para isomer is not volatile.

(c) Fractional distillation separates crude naphtha. Naphtha is a flammable liquid hydrocarbon mixture.

(d) Distillation under reduced pressure separates mixture of glycerol and sugars. Vacuum distillation lowers the boiling point and prevents decomposition.

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