Verified Solution • 2025–26 Session moderate

QJEEM18Cha3cc: JEE Main 2018 Chemistry - Class 11 JEEM18Cha3cc Solution: f G o at 500 K for substance 'S' in liquid state and gaseous…

Δ\Delta fGo at 500 K for substance 'S' in liquid state and gaseous state are +100.7 kcl mol-1 and +103 kcal mol-1, respectively. Vapour pressure of liquid 'S' at 500 K is approximately equal to : ( R = 2 cal K-1 mol-1 )

Multiple Choice Options

  • A 0.1 atm
  • B 1 atm
  • C 10 atm
  • D 100 atm

Step-by-Step Verified Solution

S( ll )   ⟶   S(g)

Δ\Delta Go = Δ\Delta fGo (Vapour) −- Δ\Delta f Go (liquid)

= 103 −- 100.7

= 2.3 kcal / mol

= 2.3 ×\times 103 cal/mol.

Δ\Delta Go = −- RT ll nk

⇒\Rightarrow    \,\,\, 2.3 ×\times 103 = −- 2.303 ×\times 2 ×\times 500 log K

⇒\Rightarrow    \,\,\, log K = −- 1

⇒\Rightarrow    \,\,\, K = 0.1 atm

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