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QJEEM18Cha08d: JEE Main 2018 Chemistry - Class 12 JEEM18Cha08d Solution: Phenol reacts with methyl chloroformate in the presence of NaOH …

Phenol reacts with methyl chloroformate in the presence of NaOH to form product A. A reacts with Br2 to form product B. A and B are respectively :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/15b5019dbc9f60b928aee6e306193ee83f4a849da5ddc2fd029f9e21c575eea8.webp
  • B https://ik.imagekit.io/novatra/photos/65f6a098aa7a739c14a544ff7307dd3287175ea8a20b9b17fa6705e6894ce267.webp
  • C https://ik.imagekit.io/novatra/photos/c50cc642854c78706907f626ec680a569b99ce245922737da340c5a2b78b55d9.webp
  • D https://ik.imagekit.io/novatra/photos/baf4786343c9270c3e03970a3b41d5e213e385ac3eae35fd77506fe493a08e57.webp

Step-by-Step Verified Solution

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 152 English Explanation 1

First in presence of OH −- ion phenol will donate H+ ion and create phenoxide ion. Then this ion will react with methyl chloroformate and carbon joined with Cl and O will be slightly positive charge due to pulling of electron towards O and Cl atom. This positive charge C atom will join with negative charged O ion in phenoxide ion and create product A.

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 152 English Explanation 2

Product A reacts with Br2 and perform electrofilic aromatic substitution and at para position Br will be added.

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