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QJEEM18Ch83c8: JEE Main 2018 Chemistry - Class 11 JEEM18Ch83c8 Solution: According to molecular orbital theory, which of the following…

According to molecular orbital theory, which of the following will not be a viable molecule?

Multiple Choice Options

  • A He22+{\rm H}e_2^{2 + }
  • B He2+{\rm H}e_2^{ + }
  • C H2−{\rm H}_2^{- }
  • D H22−{\rm H}_2^{2 - }

Step-by-Step Verified Solution

Note :

According to molecules orbital theory, when a molecule have bond order = 0 then that molecule does not exist.

(a)    \,\,\, Configuration of He22+He_2^{2 + } (2 electrons) is = σ1s2{\sigma _{1{s^2}}}

∴   \therefore\,\,\, Bond order = 12{1 \over 2} (2 −- 0) = 1

(b)    \,\,\, Configuration of He2+He_2^ + (3 electrons) is = σ1s2{\sigma _{1{s^2}}} σ1s1∗\sigma _{1{s^1}}^ *

∴   \therefore\,\,\, Bond order = 12{1 \over 2} (2 −- 1) = 0.5

(c)    \,\,\, Configuration of H2−H_2^ - (3 electrons) is = σ1s2{\sigma _{1{s^2}}} σ1s1∗\sigma _{1{s^1}}^ *

∴\therefore Bond order = 12{1 \over 2} (2 −- 1) = 0.5

(d) ∴   \therefore\,\,\, Configuration of He22−He_2^{2 - } is = σ1s2  σ1s2∗{\sigma _{1{s^2}}}\,\,\sigma _{1{s^2}}^ *

∴   \therefore\,\,\, Bond order = =12= {1 \over 2} (2 −- 2) = 0

∴   \therefore\,\,\, H22−H_2^{2 - } is not a viable molecule.

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