QJEEM18Ch7f80: JEE Main 2018 Chemistry - Class 11 JEEM18Ch7f80 Solution: A sample of is converted by heat to with a loss of of oxygen.…

NaClO₃ $$\stackrel{\mathrm{\Delta }}{⟶}$$ 2NaCl + 3O₂

Here O₂ produced = 0.16 g

$\therefore\,\,\,\,$ No of moles of O₂ = ${{0.16} \over {32}}$ = 5 $\times$ 10 ^{$-$ 3}

Let no of moles of NaCl

$\therefore\,\,\,\,$ ${{{}^nNaCl} \over 2}$ = ${{^n{O_2}} \over 3}$

$\Rightarrow$ $\,\,\,\,$ $^nNaCl$ = ${2 \over 3}$ $\times$ 5 $\times$ 10 ^{$-$ 3} = ${1 \over {300}}$

NaCl + Ag⁺ $\to$ AgCl + Na⁺

From here, you can see

no of moles in NaCl = no of moles in AgCl

$\therefore\,\,\,\,$ no of moles in AgCl = ${1 \over {300}}$

$\therefore\,\,\,\,$ Mass of AgCl = 143.5 $\times$ ${1 \over {300}}$ = 0.48 g