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QJEEM18Ch7ad8: JEE Main 2018 Chemistry - Class 11 JEEM18Ch7ad8 Solution: The de-Broglie's wavelength of electron present in first Bohr…

The de-Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is :

Multiple Choice Options

  • A 0.529 A∘
  • B 2π × 0.529 A∘
  • C 0.5292π A∘
  • D 4 × 0.529 A∘

Step-by-Step Verified Solution

Radius    r = 0.529 × n2z

In first Bohr orbit of hydrogen atom radius,

r = 0.529 × 121 = 0.529 A∘

Angular momentum,

mvr = nh2π

∴ for    n = 1,

    mvr = h2π

⇒ 2πr = hmv = λ   [ as   λ = hmv]

∴ λ = 2πr = 2 π × 0.5 29

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