Verified Solution • 2025–26 Session moderate

QJEEM18Ch759c: JEE Main 2018 Chemistry - Class 11 JEEM18Ch759c Solution: Ejection of the photoelectron from metal in the photoelectric…

Ejection of the photoelectron from metal in the photoelectric experiment can be stopped by applying 0.5 V when the radiation of 250 nm is used. The work function of the metal is :

Multiple Choice Options

  • A 4 eV
  • B 4.5 eV
  • C 5 eV
  • D 5.5 eV

Step-by-Step Verified Solution

λ\lambda = 250 nm = 2500 A∘\mathop A\limits^ \circ

E = hcλ{{hc} \over \lambda } = 124002500{{12400} \over {2500}} = 4.96 eV

K. E = 0.5 eV

As,       \,\,\,\,\,\, K. E = E −- ω\omega 0

⇒\Rightarrow    \,\,\, 0.5 = 4.96 −- ω0{\omega _0}

⇒\Rightarrow    \,\,\, ω0{\omega _0} = 4.46 eV ≃\simeq 4.5 eV

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