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QJEEM18Ch7073: JEE Main 2018 Chemistry - Class 12 JEEM18Ch7073 Solution: When XO 2 is fused with an alkali metal hydroxide in presence…

When XO2 is fused with an alkali metal hydroxide in presence of an oxidizing agent such as KNO3 ; a dark green product is formed which disproportioates in acidic solution to afforda dark purple solution. X is :

Multiple Choice Options

  • A Ti
  • B V
  • C Cr
  • D Mn

Step-by-Step Verified Solution

X is Mn.

MnO2  +  2KOH  +  KNO3   →\to   K2MnO4  +  KNO2  +  H2O

Here   K2MnO4  is dark green.

3MnO4 −- 2  +  4H+   →\to   2MnO4 −-   +  MnO2  +  2H2O

In acidic solution, K2MnO4 changes to dark purple solution of KMnO4.

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