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QJEEM18Ch7073: JEE Main 2018 Chemistry - Class 12 JEEM18Ch7073 Solution: When XO 2 is fused with an alkali metal hydroxide in presence…
When XO2 is fused with an alkali metal hydroxide in presence of an oxidizing agent such as KNO3 ; a dark green product is formed which disproportioates in acidic solution to afforda dark purple solution. X is :
Multiple Choice Options
- A Ti
- B V
- C Cr
- D Mn
Step-by-Step Verified Solution
X is Mn.
MnO2 + 2KOH + KNO3 K2MnO4 + KNO2 + H2O
Here K2MnO4 is dark green.
3MnO4 2 + 4H+ 2MnO4 + MnO2 + 2H2O
In acidic solution, K2MnO4 changes to dark purple solution of KMnO4.
MnO2 + 2KOH + KNO3 K2MnO4 + KNO2 + H2O
Here K2MnO4 is dark green.
3MnO4 2 + 4H+ 2MnO4 + MnO2 + 2H2O
In acidic solution, K2MnO4 changes to dark purple solution of KMnO4.