Verified Solution • 2025–26 Session moderate

QJEEM18Ch4ffa: JEE Main 2018 Chemistry - Class 12 JEEM18Ch4ffa Solution: The major product formed in the following reaction is :

The major product formed in the following reaction is : JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/57a7c95a36805e44ac3d399a7fd80a0ee6e0e6e4c159dbcef095e4850188f790.webp
  • B https://ik.imagekit.io/novatra/photos/a9fa067df4737f47d82644a4f0e10e57a3659b1644fa38014bd80635721d23f7.webp
  • C https://ik.imagekit.io/novatra/photos/9d54398e189b3a6dae415873cdee2402b18e38dba2c4c85ea36a5187ba28cfc0.webp
  • D https://ik.imagekit.io/novatra/photos/fb79ca41a695b5cb0c462250d00e9e06c7ea7e6afad0ff2048222a425c4643de.webp

Step-by-Step Verified Solution

(1)

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 1

Here oxygen(O) has lone so it will attach on H+ of HI and H+ will attach with O atom to form oxonium ion.

(2)

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 2

As O is more electronegative atom, so it don't want to hold the positive charge so it will break bond to create 2o cation which is stable.

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 3

Now with this cation I −- ion is added.

(3)    \,\,\, On the other oxygen atom similar method is applied.

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 4

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