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QJEEM18Ch4014: JEE Main 2018 Chemistry - Class 11 JEEM18Ch4014 Solution: An unknown chlorohydrocarbon has 3.55% of chlorine. If each…

An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 × 1023 mol-1)

Multiple Choice Options

  • A 6.023 × 1020
  • B 6.023 × 109
  • C 6.023 × 1021
  • D 6.023 × 1023

Step-by-Step Verified Solution

%    of   Cl  =  3.55

∴ In 100 g chlorohydrocarbon 3.55 gm Cl present.

In 1 gm chlorohydrocarbon Cl present

= 3.55100

= 0.0355 gm

∴ No of Moles of Cl = 0.035535.5

= 0.001 mole

∴ no of Cl atoms = 0.001 × 6.023 × 103

= 6.023 × 1020

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