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QJEEM18Ch4014: JEE Main 2018 Chemistry - Class 11 JEEM18Ch4014 Solution: An unknown chlorohydrocarbon has 3.55% of chlorine. If each…
An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 1023 mol-1)
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023
Multiple Choice Options
- A 6.023 × 1020
- B 6.023 × 109
- C 6.023 × 1021
- D 6.023 × 1023
Step-by-Step Verified Solution
% of Cl = 3.55
In 100 g chlorohydrocarbon 3.55 gm Cl present.
In 1 gm chlorohydrocarbon Cl present
=
= 0.0355 gm
No of Moles of Cl =
= 0.001 mole
no of Cl atoms = 0.001 6.023 103
= 6.023 1020
In 1 gm chlorohydrocarbon Cl present
=
= 0.0355 gm
= 0.001 mole
= 6.023