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QJEEM18Ch3be0: JEE Main 2018 Chemistry - Class 12 JEEM18Ch3be0 Solution: The major product of the following reaction is:

The major product of the following reaction is: JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/865f20743bfa69ad4108eb6b5ff6d55770ff163054aa50f0d1a4c27ab298f853.webp
  • B https://ik.imagekit.io/novatra/photos/cc6ba4ca3fa9d25bc071b633b252b6b8bae1fb3d6274a421528a95a7c72a4b1f.webp
  • C https://ik.imagekit.io/novatra/photos/6541eabfbc28b91f95cef166308ee8e23b5e0d0c705d2534899ed42dd0df8efd.webp
  • D https://ik.imagekit.io/novatra/photos/7a742886b37eabb815b4cc1a1a6afdac38d72a873434f6e93754e7c183cc6ade.webp

Step-by-Step Verified Solution

JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Explanation

OMe −- is a strong base and because of this E2 elimination will happen.

OMe −- will attack on H and make MeOH and leaving group Br will make NaBr then an ankene will be formed.

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