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QJEEM18Ch25ca: JEE Main 2018 Chemistry - Class 12 JEEM18Ch25ca Solution: In graphite and diamond, the percentage of p-characters of the…

In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively :

Multiple Choice Options

  • A 33 and 25
  • B 33 and 75
  • C 50 and 75
  • D 67 and 75

Step-by-Step Verified Solution

Hybridization of carbon in graphite is sp2.

So,   %   of p - in graphite = 23×100{2 \over 3} \times 100 = 67%

Hybridization of carbon in diamond is sp3 .

So,   %   of p - in diamond = 34×100{3 \over 4} \times 100 = 75%

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