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QJEEM17Phfc97: JEE Main 2017 Physics - Class 11 JEEM17Phfc97 Solution: The ratio of maximum acceleration to maximum velocity in a…

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s−1 . At, t = 0 the displacement is 5 m. What is the maximum acceleration ? The initial phase is π4.

Multiple Choice Options

  • A 500 m/s2
  • B 500 2m/ s2
  • C 750 m/s2
  • D 750 2m / s2

Step-by-Step Verified Solution

Mximum velocity, Vmax = aω

Maximum acceleration, Amax = aω2

Given that,

aω2aω = 10

⇒ ω = 10 s−1

Displacement, x = a sin (ωt + π4)

at t = 0, displacement x = 5

∴ 5 = a sin (π4)

⇒ 5 = a × 12

⇒ a = 52

∴ Maximum acceleration,

Amax = aω2 = 5 2 × (10)2

= 500 2 m/s2

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