QJEEM17Phf1a6: JEE Main 2017 Physics - Class 12 JEEM17Phf1a6 Solution: The acceleration of an electron in the first orbit of the…

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The acceleration of an electron in the first orbit of the hydrogen atom (n = 1) is :

Accepted Answer

The speedy of the particle in the orbit of an atom is $v = \frac{I^{2}}{2 h ε_{0}}$

We have the radius of the first orbit is

$r = \frac{h^{2} ε_{0}}{π m e^{2}}$

$\Rightarrow ε_{0} = \frac{r π m e^{2}}{h^{2}}$

Therefore, the acceleration of an electron in the first orbit of the hydrogen atom (n = 1) is

$\frac{v^{2}}{r} = \frac{I^{6} π m}{4 h^{2} ε_{0}^{3}} = \frac{h^{2}}{4 r^{3} π^{2} m^{2}}$

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