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QJEEM17Phea9f: JEE Main 2017 Physics - Class 11 JEEM17Phea9f Solution: A conical pendulum of length 1 m makes an angle = 45 o w.r.t.…

A conical pendulum of length 1 m makes an angle θ\theta = 45o w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be: (Take g = 10 ms−2 )

JEE Main 2017 (Online) 9th April Morning Slot Physics - Circular Motion Question 60 English

Multiple Choice Options

  • A 0.4 m/s
  • B 4 m/s
  • C 0.2 m/s
  • D 2 m/s

Step-by-Step Verified Solution

FBD of pendulum is :

JEE Main 2017 (Online) 9th April Morning Slot Physics - Circular Motion Question 60 English Explanation

∴   \therefore\,\,\, T sin θ\theta = mv2r{{m{v^2}} \over r}

     T cos θ\theta = mg

∴   \therefore\,\,\, tan θ\theta = v2rg{{{v^2}} \over {rg}}

⇒\Rightarrow    \,\,\, tan45o = v2rg{{{v^2}} \over {rg}}

⇒\Rightarrow    \,\,\, v2 = rg

⇒\Rightarrow    \,\,\, v = 0.4×10\sqrt {0.4 \times 10} = 2 m/s

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