Verified Solution • 2025–26 Session moderate

QJEEM17Phb52c: JEE Main 2017 Physics - Class 11 JEEM17Phb52c Solution: Which graph corresponds to an object moving with a constant…

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity ?

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/e3d2e15b57cfd6137ad0a064e3031f32ca5c687ae4556427951dc7e067e351fa.webp
  • B https://ik.imagekit.io/novatra/photos/e5d266c6910cce233c97b5e4e52eabfc1c55d602328ac56e0756ba95dd753227.webp
  • C https://ik.imagekit.io/novatra/photos/de7576b1c42b9fdfd2f177eb67ff93633ae8af459b6091861a0935d36c269644.webp
  • D https://ik.imagekit.io/novatra/photos/d703eebc37a4c017eef30792601523eac23d554b7eacde7ed6ffaa2a40f29fa9.webp

Step-by-Step Verified Solution

Given that,

acceleration (a) = −- C (constant)

∴   \therefore\,\,\, dvdt{{dv} \over {dt}} = −- c

⇒\Rightarrow    \,\,\, dvdx{{dv} \over {dx}} . dxdt{{dx} \over {dt}} = −- c

⇒\Rightarrow    \,\,\, υ\upsilon dvdx{{dv} \over {dx}} = −- c

⇒\Rightarrow    \,\,\, ∫v dv\int {v\,dv} = −- c ∫dx\int {dx}

⇒\Rightarrow    \,\,\, v22{{{v^2}} \over 2} = −- cx + k

⇒\Rightarrow    \,\,\, x = −- v22c{{{v^2}} \over {2c}} + kc{k \over c}

From this equation we can say option (c) is the correct graph.

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