Verified Solution • 2025–26 Session moderate

QJEEM17Pha4aa: JEE Main 2017 Physics - Class 12 JEEM17Pha4aa Solution: An electron beam is accelerated by a potential difference V to…

An electron beam is accelerated by a potential difference V to hit a metallic target to produce X–rays. It produces continuous as well as characteristic X-rays. If λmin is the smallest possible wavelength of X-ray in the spectrum, the variation of logλmin with log V is correctly represented in:

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/1879e3bd240b0ca3ea5a73f0de98a4d106cdcef3088229aa22587ca94cd351ac.webp
  • B https://ik.imagekit.io/novatra/photos/e3b0f10f25482dd5162557d163ffbd107f3547fab77c6e2aa0ef8de6e87b2f72.webp
  • C https://ik.imagekit.io/novatra/photos/89298ef3be38df2d6bbcf9d93e3480313003d6bde2572dac2f19110adf761f33.webp
  • D https://ik.imagekit.io/novatra/photos/7ee402190c4450ab49f045d2b169215e8562c2db774d2b2b61eec9fb2312594d.webp

Step-by-Step Verified Solution

In X-ray tube, λmin=hceV

log⁡(λmin)=log⁡(hce)−log⁡V

Clearly, log (λmin) versus log V graph slope is negative hence option (b) is correct.

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