Verified Solution • 2025–26 Session moderate

QJEEM17Ph963d: JEE Main 2017 Physics - Class 11 JEEM17Ph963d Solution: A time dependent force F = 6t acts on a particle of mass 1 kg.…

A time dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 sec. will be:

Multiple Choice Options

  • A 18 J
  • B 4.5 J
  • C 22 J
  • D 9 J

Step-by-Step Verified Solution

Given that, F = 6t

We know, F = ma = mdvdt

∴ mdvdt=6t

⇒ 1.dvdt=6t [as m = 1]

⇒ ∫0vdv=∫6tdt

⇒ v=6[t22]01

⇒ v=62=3 m/s [ as given t = 1 sec ]

Work done by the body during the first 1 form work-energy theorem,

W = ΔK.E = 12m(V2−v2)

= 12.1.(32−02) = 4.5 J

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