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QJEEM17Ph5cf6: JEE Main 2017 Physics - Class 12 JEEM17Ph5cf6 Solution: A capacitance of 2 F is required in an electrical circuit…

A capacitance of 2 μ\mu F is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1 μ\mu F capacitors are available which can withstand a potential difference of not more than 300 V. The minimum number of capacitors required to achieve this is:

Multiple Choice Options

  • A 2
  • B 16
  • C 32
  • D 24

Step-by-Step Verified Solution

To get a capacitance of 2 μF arrangement of capacitors of capacitance 1μF as shown in figure 8 capacitors of 1μF in parallel with four such branches in series i.e., 32 such capacitors are required. JEE Main 2017 (Offline) Physics - Capacitor Question 135 English Explanation

1Ceq=18+18+18+18{1 \over {{C_{eq}}}} = {1 \over 8} + {1 \over 8} + {1 \over 8} + {1 \over 8}

⇒\Rightarrow 1Ceq=12{1 \over {{C_{eq}}}} = {1 \over 2}

⇒\Rightarrow Ceq=2{{C_{eq}} = 2}

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