Verified Solution • 2025–26 Session moderate

QJEEM17Ph3483: JEE Main 2017 Physics - Class 11 JEEM17Ph3483 Solution: The variation of acceleration due to gravity g with distance d…

The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R = Earth’s radius):

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/cd6f7942aa9879bdfaf2a504058876d707a4267048605083899a290358faf366.webp
  • B https://ik.imagekit.io/novatra/photos/7fcbb5148bfb876fc974444b0d3edd242ec669ec63e0efcfa9c1a06c256eebc4.webp
  • C https://ik.imagekit.io/novatra/photos/138ab4d9937883f696358c3c58a2fdeaf2ef15aa88ad61cafbc3efa674125e52.webp
  • D https://ik.imagekit.io/novatra/photos/9a50df96e09ede61c58606b846dcd00c69bc1ced6cda321ffd581f088217b436.webp

Step-by-Step Verified Solution

When d < R means distance of a point is d from the center of the circle where d is inside the earth surface. In this case the value of acceleration, g=−GMdR3

∴ g∝d

So inside of the earth surface g - d graph is straight line.

When d > R means distance of a point is d from the center of the circle where d is outside of the earth's surface. In this case the value of acceleration, g=−GMd2

∴ g∝1d2

So outside of the earth surface g - d graph is hyperbolic.

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