Verified Solution • 2025–26 Session moderate

QJEEM17Ph1308: JEE Main 2017 Physics - Class 12 JEEM17Ph1308 Solution: A diverging lens with magnitude of focal length 25 cm is placed …

A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15cm from a converging lens of magnitude of focal length 20cm. A beam of parallel light falls on the diverging lens. The final image formed is:

Multiple Choice Options

  • A real and at a distance of 6 cm from the convergent lens.
  • B real and at a distance of 40 cm from convergent lens.
  • C virtual and at a distance of 40 cm from convergent lens.
  • D real and at a distance of 40 cm from the divergent lens.

Step-by-Step Verified Solution

As parallel beam incident on diverging lens so the image will be formed at the focus of diverging lens.

∴\therefore v = –25 cm JEE Main 2017 (Offline) Physics - Geometrical Optics Question 190 English Explanation
The image formed by diverging lens is used as an object for converging lens.

So for converging lens

u = –25 – 15 = –40 cm,

f = 20 cm

So Final image formed by converging lens

120=1V−1−40{1 \over {20}} = {1 \over V} - {1 \over { - 40}}

⇒\Rightarrow V = 40 cm

V is positive so image will be real and will form at right side of converging lens at 40 cm.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring