Verified Solution • 2025–26 Session moderate

QJEEM17Maf8d9: JEE Main 2017 Mathematics - Class 12 JEEM17Maf8d9 Solution: Three persons P, Q and R independently try to hit a target. I…

Three persons P, Q and R independently try to hit a target. I the probabilities of their hitting the target are 34,12{3 \over 4},{1 \over 2} and 58{5 \over 8} respectively, then the probability that the target is hit by P or Q but not by R is :

Multiple Choice Options

  • A 2164{{21} \over {64}}
  • B 964{{9} \over {64}}
  • C 1564{{15} \over {64}}
  • D 3964{{39} \over {64}}

Step-by-Step Verified Solution

We have the following probabilities:

∙\bullet The probability that the target is hit by the person P is 34{3 \over 4} .

∙\bullet The probability that the target is not hit by the person P is 1−34=141 - {3 \over 4} = {1 \over 4} .

∙\bullet The probability that the target is hit by the person Q is 12{1 \over 2} .

∙\bullet The probability that the target is not hit by the person Q is 1−12=121 - {1 \over 2} = {1 \over 2} .

∙\bullet The probability that the target is hit by the person R is 58{5 \over 8} .

∙\bullet The probability that the target is not hit by the person R is 1−58=381 - {5 \over 8} = {3 \over 8} .

Here, we have used the fact that if the probability of occurrence of an event is p, then the probability of non-occurrence of an event is q=1−pq = 1 - p .

Therefore, the probability that the target is hit by P or Q and not by R is

(Probability that the target is hit by P and not by Q and R) + (Probability that the target is hit by Q and not by P and R) + (Probability that the target is hit by both P and Q and not by R)

=(34)(12)(38)+(14)(12)(38)+(34)(12)(38)= \left( {{3 \over 4}} \right)\left( {{1 \over 2}} \right)\left( {{3 \over 8}} \right) + \left( {{1 \over 4}} \right)\left( {{1 \over 2}} \right)\left( {{3 \over 8}} \right) + \left( {{3 \over 4}} \right)\left( {{1 \over 2}} \right)\left( {{3 \over 8}} \right)

=964+364+964=9+3+964=2164= {9 \over {64}} + {3 \over {64}} + {9 \over {64}} = {{9 + 3 + 9} \over {64}} = {{21} \over {64}}

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