Verified Solution • 2025–26 Session moderate

QJEEM17Ma65e1: JEE Main 2017 Mathematics - Class 12 JEEM17Ma65e1 Solution: If ( 2 + sin ⁡ x ) d y d x + ( y + 1 ) cos ⁡ x = 0 and y(0) =…

If (2+sin⁡x)dydx+(y+1)cos⁡x=0 and y(0) = 1,

then y(π2) is equal to :

Multiple Choice Options

  • A −23
  • B −13
  • C 43
  • D 13

Step-by-Step Verified Solution

(2+sin⁡x)dydx+(y+1)cos⁡x=0

⇒ ddx(2+sin⁡x)(y+1)=0

On integrating, we get

(2 + sin x) (y + 1) = C

At x = 0, y = 1 we have

(2 + sin 0) (1 + 1) = C

⇒ C = 4

⇒ (y+1)=42+sin⁡x

⇒ y = 42+sin⁡x−1

Now y(π2)=42+sin⁡π2−1

= 43−1 = 13

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