Verified Solution • 2025–26 Session moderate

QJEEM17Ma04d1: JEE Main 2017 Mathematics - Class 12 JEEM17Ma04d1 Solution: The integral is equal to

The integral ∫π43π4dx1+cos⁡x\int\limits_{{\pi \over 4}}^{{{3\pi } \over 4}} {{{dx} \over {1 + \cos x}}} is equal to

Multiple Choice Options

  • A 2
  • B 4
  • C −- 1
  • D −- 2

Step-by-Step Verified Solution

∫π43π4dx1+cos⁡x\int\limits_{{\pi \over 4}}^{{{3\pi } \over 4}} {{{dx} \over {1 + \cos x}}}

= ∫π43π4dx2cos⁡2x2\int\limits_{{\pi \over 4}}^{{{3\pi } \over 4}} {{{dx} \over {2{{\cos }^2}{x \over 2}}}}

= 12∫π43π4sec⁡2x2 dx{1 \over 2}\int\limits_{{\pi \over 4}}^{{{3\pi } \over 4}} {{{\sec }^2}} {x \over 2}\,dx

12[tan⁡x212]π43π4{1 \over 2}\left[ {{{\tan {x \over 2}} \over {{1 \over 2}}}} \right]_{{\pi \over 4}}^{{{3\pi } \over 4}}

= [tan⁡x2]π434\left[ {\tan {x \over 2}} \right]_{{\pi \over 4}}^{{3 \over 4}}

= tan 3π8{{3\pi } \over 8} −- tan π8{\pi \over 8}

= (2+1)−(2−1)\left( {\sqrt 2 + 1} \right) - \left( {\sqrt 2 - 1} \right)

= 2

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