QJEEM17Cha6f5: JEE Main 2017 Chemistry - Class 12 JEEM17Cha6f5 Solution: On treatment of 100 mL of 0.1 M solution of CoCl 3 . 6H 2 O…

Question

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On treatment of 100 mL of 0.1 M solution of CoCl₃. 6H₂O with excess AgNO₃; 1.2

\times

10²² ions are precipitated. The complex is :

Accepted Answer

Moles of complex =

\frac{M o l a r i t y \times V o l u m e (m L)}{1000}

=

\frac{100 \times 0.1}{1000}

= 0.01 mole

Moles of ions precipitated with excess of AgNO₃

=

\frac{1.2 \times 10^{22}}{6.023 \times 10^{23}}

= 0.02 mole

So 0.01 × n = 0.02

\Rightarrow

n = 2

It means 2Cl^– ions present in ionization sphere.

∴

The formula of complex is [Co(H₂O)₅Cl]Cl₂.H₂O

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