Verified Solution • 2025–26 Session moderate

QJEEM17Cha49c: JEE Main 2017 Chemistry - Class 12 JEEM17Cha49c Solution: Given E C l 2 / C l − o = 1.36 V, E C r 3 + / C r o = - 0.74 V…

Given
ECl2/Cl−o = 1.36 V, ECr3+/Cro = - 0.74 V
ECr2O72−/Cr3+o = 1.33 V, EMnO4−/Mn2+o = 1.51 V
Among the following, the strongest reducing agent is :

Multiple Choice Options

  • A Mn2+
  • B Cr3+
  • C Cl–
  • D Cr

Step-by-Step Verified Solution

ECl2/Cl−o = 1.36 V, ECr3+/Cro = - 0.74 V
ECr2O72−/Cr3+o = 1.33 V, EMnO4−/Mn2+o = 1.51 V

More negative the E° value of the species, more stronger is the reducing agent. Since Cr3+ is having least reducing potential, so Cr would be strongest reducing agent.

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