Verified Solution • 2025–26 Session moderate

QJEEM17Ch6c77: JEE Main 2017 Chemistry - Class 11 JEEM17Ch6c77 Solution: The radius of the second Bohr orbit for hydrogen atom is:…

The radius of the second Bohr orbit for hydrogen atom is:
(Planck’s Const. h = 6.6262 × 10-34 Js; mass of electron = 9.1091 × 10-31 kg; charge of electron (e) = 1.60210 × 10-19 C; permittivity of vacuum ( ε0{\varepsilon _0} ) = 8.854185 × 10-12 kg-1 m-3 A2)

Multiple Choice Options

  • A 4.76 Ao\mathop {\rm A}\limits^o
  • B 2.12 Ao\mathop {\rm A}\limits^o
  • C 0.529 Ao\mathop {\rm A}\limits^o
  • D 1.65 Ao\mathop {\rm A}\limits^o

Step-by-Step Verified Solution

Radius of an atom in nth orbit,

rn = 0.529 ×n2Z\times {{{n^2}} \over Z}

Here n = 2

and for hydrogen atom, atomic number (Z) = 1

∴\therefore r2 = 0.529 ×221\times {{{2^2}} \over 1} = 2.12 Ao\mathop {\rm A}\limits^o

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