Verified Solution • 2025–26 Session moderate

QJEEM17Ch3e37: JEE Main 2017 Chemistry - Class 12 JEEM17Ch3e37 Solution: What is the standard reduction potential (E o ) for Fe 3+ Fe ?…

What is the standard reduction potential (Eo) for Fe3+ →\to Fe ?
Given that :
Fe2+ + 2e −- →\to Fe; EFe2+/FeoE_{F{e^{2 + }}/Fe}^o = −- 0.47 V
Fe3+ + e −- →\to Fe2+; EFe3+/Fe2+oE_{F{e^{3 + }}/F{e^{2 + }}}^o = +0.77 V

Multiple Choice Options

  • A −- 0.057 V
  • B + 0.057 V
  • C + 0.30 V
  • D −- 0.30 V

Step-by-Step Verified Solution

For the given reaction :

Fe3+ + e −- →\to Fe2+; EFe3+/Fe2+oE_{F{e^{3 + }}/F{e^{2 + }}}^o = +0.77 V

Δ\Delta Go = -nFEo

⇒\Rightarrow ΔG1o=−(1)F(0.77)\Delta G_1^o = - \left( 1 \right)F\left( {0.77} \right) = -0.77F

For the following reaction :

Fe2+ + 2e −- →\to Fe; EFe2+/FeoE_{F{e^{2 + }}/Fe}^o = −- 0.47 V

ΔG2o=−(2)F(−0.47)\Delta G_2^o = - \left( 2 \right)F\left( {-0.47} \right) = 0.47 ×\times 2F

Overall reaction :

Fe3+ + 3e −- →\to Fe;

ΔG3o=−3FE3o\Delta G_3^o = - 3FE_3^o

⇒\Rightarrow ΔG1o\Delta G_1^o + ΔG2o\Delta G_2^o = 3FE3o3FE_3^o

⇒\Rightarrow -0.77F + 0.47 ×\times 2F = 3FE3o3FE_3^o

⇒\Rightarrow E3o=−0.173E_3^o = - {{0.17} \over 3} = -0.057 V

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