QJEEM16Phf1dd: JEE Main 2016 Physics - Class 12 JEEM16Phf1dd Solution: An experiment is performed to determine the I - V…

Potential drop accross zener diode.

V_z = V $$-$$ 100 I

$$\therefore$$   Power dissiption = V_z I

= (V $$-$$ 100 I) I

Given that,

(V $$-$$ 100 I) I = 1

$$\Rightarrow$$   VI $$-$$ 100 I² = 1

$$\Rightarrow$$   100 I² $$-$$ VI + 1 = 0

As   As I is real,

So, b² $$-$$ 4ac $$\ge$$ far this quadratic equation.

$$\therefore$$   V² $$-$$ 4(100)1  $$\ge$$ 0

$$\Rightarrow$$   V $$\ge$$ 20 V

$$\therefore$$   Voltage range should be 0 $$-$$ 24 V