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QJEEM16Phecb9: JEE Main 2016 Physics - Class 11 JEEM16Phecb9 Solution: A, B, C and D are four different physical quantities having…

A, B, C and D are four different physical quantities having different dimensions. None of them is dimensionless. But we know that the equation AD = C ln (BD) holds true. Then which of the combination is not a meaningful quantity ?

Multiple Choice Options

  • A A2 −- B2C2
  • B (A−C)D{{\left( {A - C} \right)} \over D}
  • C AB−C{A \over B} - C
  • D CBD−AD2C{C \over {BD}} - {{A{D^2}} \over C}

Step-by-Step Verified Solution

Given,

AD = c ln (BD)

As log is dimensionless.

So, [BD] = 1    ⇒\Rightarrow   [B] = 1[D]{1 \over {\left[ D \right]}}

And  [AD] = [C]

Now checking options one by one

(a)   [B2 C2] = [B2] [A2 D2] = [A2] [B2 D2] = [A2]

∴\therefore    This is meaningful.

(b)    (A−CD)\left( {{{A - C} \over D}} \right) is not meaningful.

As dimension of A ≠\ne dimension of C

Hence (A −- C)   is not possible.

(c)    [AB]\left[ {{A \over B}} \right] = [AD] = [C]

∴\therefore     AB{{A \over B}} −- C is meaningful.

(d)    [CBD]\left[ {{C \over {BD}}} \right] = [C][BD]{{\left[ C \right]} \over {\left[ {BD} \right]}} = [C]1{{\left[ C \right]} \over 1} = [C]

[AD2C]\left[ {{{A{D^2}} \over C}} \right] = [AD][D][C]{{\left[ {AD} \right]\left[ D \right]} \over {\left[ C \right]}} = [C][D][C]{{\left[ C \right]\left[ D \right]} \over {\left[ C \right]}} = [D]

As dimension of C and D are not same so it is not meaning ful.

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