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QJEEM16Phc941: JEE Main 2016 Physics - Class 11 JEEM16Phc941 Solution: A particle of mass M is moving in a circle of fixed radius R in …

A particle of mass M is moving in a circle of fixed radius R in such a way that its centripetal acceleration at time t is given by n2 R t2 where n is a constant. The power delivered to the particle by the force acting on it, is :

Multiple Choice Options

  • A M n2 R2 t
  • B M n R2 t
  • C M n R2 t2
  • D 12 M n2 R2 t2

Step-by-Step Verified Solution

We know,

centripetal acceleration = V2R

∴   According to question,

V2R = n2Rt2

⇒   V2 = n2 R2 t2

⇒   V = nRt

⇒   dVdt = nR

Power (P) = Force (F) × Velocity (V)

= M dVdt(V)

= M (nR) (nRt)

= Mn2R2t

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