QJEEM16Ph96b8: JEE Main 2016 Physics - Class 11 JEEM16Ph96b8 Solution: A thin 1 m long rod has a radius of 5 mm. A force of 50 π kN is …

Question

Verified Solution • 2025–26 Session moderate

QJEEM16Ph96b8: JEE Main 2016 Physics - Class 11 JEEM16Ph96b8 Solution: A thin 1 m long rod has a radius of 5 mm. A force of 50 π kN is …

A thin 1 m long rod has a radius of 5 mm. A force of 50

π

kN is applied at one end to determine its Young’s modulus. Assume that the force is exactly known. If the least count in the measurement of all lengths is 0.01 mm, which of the following statements is false ?

Multiple Choice Options

A Δγγ gets minimum contribution from the uncertainty in the length.
B The figure of merit is the largest for the length of the rod.
C The maximum value of γ that can be determined is 2 × 1014 N/m2
D Δγγ gets its maximum contribution from the uncertainty in strain

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

Young's Modulus of the material of the rod is

$Y = \frac{S t r e s s}{S t r a i n} = \frac{(F / A)}{(Δ l / l)}$

Here, Y remains maximum, when $Δ$ l is of least count.

That is,

$Y_{max} = [\frac{50 π \times 10^{3} N}{π {(5 \times 10^{- 3})}^{2} m^{2}}] [\frac{1 m}{0.01 \times 10^{- 3} m}]$

$= 2 \times 10^{4} N / m^{2}$

QJEEM16Ph96b8: JEE Main 2016 Physics - Class 11 JEEM16Ph96b8 Solution: A thin 1 m long rod has a radius of 5 mm. A force of 50 π kN is …

Multiple Choice Options

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation