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QJEEM16Ph6b0b: JEE Main 2016 Physics - Class 11 JEEM16Ph6b0b Solution: In an engine the piston undergoes vertical simple harmonic…

In an engine the piston undergoes vertical simple harmonic motion with amplitude 7 cm. A washer rests on top of the piston and moves with it. The motor speed is slowly increased. The frequency of the piston at which the washer no longer stays in contact with the piston, is close to :

Multiple Choice Options

  • A 0.1 Hz
  • B 1.2 Hz
  • C 0.7 Hz
  • D 1.9 Hz

Step-by-Step Verified Solution

Here,

Amplitude, A = 7 cm = 0.07 m

When washer is no longer stays in contact with the piston, then the normal force on the washer is = 0

∴\therefore    Maximum acceleration of the washer,

amax = ω\omega 2A = g

⇒\Rightarrow     ω\omega = gA\sqrt {{g \over A}} = 100.07\sqrt {{{10} \over {0.07}}} = 10007\sqrt {{{1000} \over 7}}

∴\therefore    Frequency of the piston,

f = ω2π{\omega \over {2\pi }} = 12π10007{1 \over {2\pi }}\sqrt {{{1000} \over 7}} = 1.9 Hz

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