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QJEEM16Ph64eb: JEE Main 2016 Physics - Class 11 JEEM16Ph64eb Solution: 200 g water is heated from 40 o C to 60 o C. Ignoring the…

200 g water is heated from 40oC to 60oC. Ignoring the slight expansion of water, the change in its internal energy is close to (Given specific heat of water = 4184 J/kg/K) :

Multiple Choice Options

  • A 8.4 kJ
  • B 4.2 kJ
  • C 16.7 kJ
  • D 167.4 kJ

Step-by-Step Verified Solution

According to the first law of thermodynamics,

Q = Δu + w

For isochoric process Q = ΔU = msΔt

ΔT = (233 − 213) = 20 k

∴   Δu = 0.2 × 4184 × 20 = 16.7 kJ

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