QJEEM16Ph581a: JEE Main 2016 Physics - Class 12 JEEM16Ph581a Solution: Three capacitors each of 4 μ F are to be connected in such a…

Question

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Three capacitors each of 4

μ

F are to be connected in such a way that the effective capacitance is 6

μ

F. This can be done by connecting them :

Accepted Answer

(a)

\frac{1}{C_{e q}} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4} = \frac{3}{4}

\Rightarrow

C_{e q} = \frac{4}{3} μ F

(b)

C_{e q} = \frac{4 \times 4}{4 + 4} + 4 = 6 μ F

(c)

C_{e q} = 4 + 4 + 4 = 12 μ F

(d)

C_{e q} = \frac{(4 + 4) \times 4}{(4 + 4) + 4} = \frac{8}{3} μ F

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