QJEEM16Ph2c54: JEE Main 2016 Physics - Class 12 JEEM16Ph2c54 Solution: A convex lens, of focal length 30 cm, a concave lens of focal…

For convex lens,

$$\frac{1}{30}=\frac{1}{V_1}+\frac{1}{60}$$

$$\Rightarrow$$  $$\frac{1}{V_1}=\frac{1}{60}$$

$$\Rightarrow$$  $$V_1=60$$ cm

For concave lens,

$$\frac{1}{-120}=\frac{1}{V_2}-\frac{1}{40}$$

$$\Rightarrow$$  $$\frac{1}{V_2}=\frac{1}{60}$$

$$\Rightarrow$$  $$V_2=60$$ cm

object will be at 60 cm distance from concave lens.

As mirror distance is 50 cm from concave lens. So virtual object is 10 cm behind mirror.

So, real image is 10 cm infront of mirror.

Distance of image from concave lens $$=$$ 50 $$-$$ 10 $$=$$ 40 cm. Which is same for the real object.

So similar situation will happen and final image will form at the real object it self.