QJEEM16Ph0c5c: JEE Main 2016 Physics - Class 12 JEEM16Ph0c5c Solution: An audio signal consists of two distinct sounds : one a human…

To calculate the ratio of the AM signal bandwidth required to send both the signals together to the AM signal bandwidth required to send just the human speech, we need to consider the frequency range covered by both signals.

For the human speech signal, the frequency band is from 200 Hz to 2700 Hz. Therefore, the bandwidth required to send just the human speech is :

Bandwidth for speech = 2700 Hz - 200 Hz = 2500 Hz

For the high-frequency music signal, the frequency band is from 10200 Hz to 15200 Hz. So, the bandwidth required to send the music signal is :

Bandwidth for music = 15200 Hz - 10200 Hz = 5000 Hz

To send both signals together, we need to consider the combined frequency range. The combined frequency range covers from 200 Hz to 15200 Hz. Hence, the bandwidth required to send both signals together is :

Total bandwidth = 15200 Hz - 200 Hz = 15000 Hz

Now, let's calculate the ratio :

Ratio = Total bandwidth / Bandwidth for speech

$$\Rightarrow$$ Ratio = 15000 Hz / 2500 Hz

$$\Rightarrow$$ Ratio = 6

Therefore, the correct answer is Option C : 6.