Verified Solution • 2025–26 Session moderate

QJEEM16Ph037a: JEE Main 2016 Physics - Class 12 JEEM16Ph037a Solution: The truth table given in fig. represents : .tg…

The truth table given in fig. represents :
A B Y
0 0 0
0 1 1
1 0 1
1 1 1

Multiple Choice Options

  • A AND - Gate
  • B OR - Gate
  • C NAND - Gate
  • D NOR - Gate

Step-by-Step Verified Solution

Here   Y = 1   when,

(1)   A = 0  and   B = 1   (A‾B)\left( {\overline A B} \right)

(2)   A = 1  and  B = 0    (A B‾)\left( {A\,\overline B } \right)

(3)   A = 1  and  B = 1   (A B)\left( {A\,B} \right)

∴\therefore    Y = A‾{\overline A } B + A B‾{\overline B } + AB

= A‾{\overline A } B + A ( B‾{\overline B } + B)

= A‾{\overline A } B + A    [as   B‾{\overline B } + B = 1]

= (A + A‾{\overline A } ) (A + B)

= A + B

So, this represented OR gate.

Note :

X + X‾{\overline X } Y = (X + X‾{\overline X } ) (X + Y)

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring