Verified Solution • 2025–26 Session moderate

QJEEM16Mae822: JEE Main 2016 Mathematics - Class 12 JEEM16Mae822 Solution: If    then 'a' is equal to :

If    lim⁡x→∞(1+ax−4x2)2x=e3,\mathop {\lim }\limits_{x \to \infty } {\left( {1 + {a \over x} - {4 \over {{x^2}}}} \right)^{2x}} = {e^3}, then 'a' is equal to :

Multiple Choice Options

  • A 2
  • B 32{3 \over 2}
  • C 23{2 \over 3}
  • D 12{1 \over 2}

Step-by-Step Verified Solution

Given,

lim⁡x→∝(1+ax−4x2)2x=e3\mathop {\lim }\limits_{x \to \propto } {\left( {1 + {a \over x} - {4 \over {{x^2}}}} \right)^{2x}} = {e^3}

So,    lim⁡x→∝(1+ax−4x2)2x [1∝   form]\mathop {\lim }\limits_{x \to \propto } {\left( {1 + {a \over x} - {4 \over {{x^2}}}} \right)^{2x}}\,\left[ {{1^ \propto }\,\,\,form} \right]

=elim⁡x→∝[(1+ax−4x2−1)2x]= {e^{\mathop {\lim }\limits_{x \to \propto } \left[ {\left( {1 + {a \over x} - {4 \over {{x^2}}} - 1} \right)2x} \right]}}

=elim⁡x→∝(2a−8x)= {e^{\mathop {\lim }\limits_{x \to \propto } \left( {2a - {8 \over x}} \right)}}

=e2a= {e^{2a}}

∴\therefore    e2a = e3

∴\therefore     2a = 3

⇒\Rightarrow    a == 32{3 \over 2}

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