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QJEEM16Macaed: JEE Main 2016 Mathematics - Class 12 JEEM16Macaed Solution: The area (in sq. units) of the region described by A= {(x, y) y …

The area (in sq. units) of the region described by

A= {(x, y) ∣\left| {} \right. y ≥\ge x2 −- 5x + 4, x + y ≥\ge 1, y ≤\le 0} is :

Multiple Choice Options

  • A 72{7 \over 2}
  • B 196{{19} \over 6}
  • C 136{{13} \over 6}
  • D 176{{17} \over 6}

Step-by-Step Verified Solution

JEE Main 2016 (Online) 9th April Morning Slot Mathematics - Area Under The Curves Question 122 English Explanation

Required Area

= A1 + A2

= ∣∫13(1−x)dx∣+∣∫34(x2−5x+4)dx∣\left| {\int\limits_1^3 {\left( {1 - x} \right)} dx} \right| + \left| {\int\limits_3^4 {\left( {{x^2} - 5x + 4} \right)dx} } \right|

= ∣[x−x22]13∣+∣[x33−52x2+4x]34∣\left| {\left[ {x - {{{x^2}} \over 2}} \right]_1^3} \right| + \left| {\left[ {{{{x^3}} \over 3} - {5 \over 2}{x^2} + 4x} \right]_3^4} \right|

= ∣[(3−92)−(1−12)]∣+∣[(643−40+16)−(9−452+12)]∣\left| {\left[ {\left( {3 - {9 \over 2}} \right) - \left( {1 - {1 \over 2}} \right)} \right]} \right| + \left| {\left[ {\left( {{{64} \over 3} - 40 + 16} \right) - \left( {9 - {{45} \over 2} + 12} \right)} \right]} \right|

= ∣(2−4)∣+∣(−83+32)∣\left| {\left( {2 - 4} \right)} \right| + \left| {\left( {{{ - 8} \over 3} + {3 \over 2}} \right)} \right|

= 2 + 76{7 \over 6}

= 196{{19} \over 6} sq. unit.

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