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QJEEM16Ma5b42: JEE Main 2016 Mathematics - Class 11 JEEM16Ma5b42 Solution: If one of the diameters of the circle, given by the equation,…

If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0,{x^2} + {y^2} - 4x + 6y - 12 = 0, is a chord of a circle SS , whose centre is at (−3,2)(-3, 2) , then the radius of SS is :

Multiple Choice Options

  • A 55
  • B 1010
  • C 525\sqrt 2
  • D 535\sqrt 3

Step-by-Step Verified Solution

JEE Main 2016 (Offline) Mathematics - Circle Question 139 English Explanation

Center of SS : O(−3,2)O(-3, 2) center of given circle A(2,−3)A(2, -3)

⇒OA=52\Rightarrow OA = 5\sqrt 2

Also AB=5AB=5 (as AB=rAB=r of the given circle)

⇒\Rightarrow Using pythagoras theorem in ΔOAB\Delta OAB

r=53r = 5\sqrt 3

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