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QJEEM16Che86e: JEE Main 2016 Chemistry - Class 12 JEEM16Che86e Solution: Oxidation of succinate ion produces ethylene and carbon dioxide …

Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is :

Multiple Choice Options

  • A 2.24 L
  • B 4.48 L
  • C 6.72 L
  • D 8.96 L

Step-by-Step Verified Solution

The reaction is

2CH3COOK+2H2O⟶ElectrolysisCH3−CH3+2CO2+H2+2KOH

At the anode (Oxidation):

JEE Main 2016 (Online) 10th April Morning Slot Chemistry - Electrochemistry Question 151 English Explanation

At the cathode (Reduction):

2H2O⟶+2e−2OH−+2H∙

2H∙⟶H2

Total number of moles of gases

= moles of C2H6 + moles of CO2 + moles of H2

n=0.22+0.21+0.22=0.4n = {{0.2} \over 2} + {{0.2} \over 1} + {{0.2} \over 2} = 0.4

V=nRTpV = {{nRT} \over p}

=(0.4×0.0821×273)1=8.96= {{(0.4 \times 0.0821 \times 273)} \over 1} = 8.96 L

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