Verified Solution • 2025–26 Session moderate

QJEEM16Chcc39: JEE Main 2016 Chemistry - Class 11 JEEM16Chcc39 Solution: The amount of arsenic pentasulphide that can be obtained when…

The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid istreated with excess H2S in the presence of conc. HCl ( assuming 100% conversion) is :

Multiple Choice Options

  • A 0.50 mol
  • B 0.25 mol
  • C 0.125 mol
  • D 0.333 mol

Step-by-Step Verified Solution

2H3 As O4 + 5H2S  ⟶HClconc   As2S5 + 8H2O

35.5 g of H3AsO4 = 35.5142 = 0.25 moles

Let, As2S5 produced = n moles.

∴ 0.252=n1

⇒ n = 0.125 mol.

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